Find percentage of given five subject in 'C'

Example



#include<stdio.h>
#include<conio.h>
void main()
{
int m1,m2,m3,m4,m5,sum=0;
float per;
clrscr();
printf("Enter marks m1:");
scanf("%d",&m1);
printf("Enter marks m2:");
scanf("%d",&m2);
printf("Enter marks m3:");
scanf("%d",&m3);
printf("Enter marks m4:");
scanf("%d",&m4);
printf("Enter marks m5:");
scanf("%d",&m5);
sum=m1+m2+m3+m4+m5;
per=sum/5;
printf(" Sum of marks is=%d",sum);
printf("\n Percentage of marks is=%.2f",per);
if(m1<100 && m2<100 && m3<100 && m4<100 && m5<100)
{
if(m1>35 && m2>35 && m3>35 && m4>35 && m5>35)
{
if(per>=70)
{
printf("\nClass=Distinction");
}
else if(per>=60 && per<70)
{
printf("\nClass=First");
}
else if(per>=50 && per<60)
{
printf("\nClass=Second");
}
else if(per>=35 && per<50)
{
printf("\nClass=Pass");
}
       }   else
       {
if((m1<35 && m2<35) || (m2<35 && m3<35) || (m3<35 && m4<35) || (m4<35 && m5<35) || (m5<35 && m1<35) || m1<35 || m2<35 || m3<35 || m4<35 || m5<35)
{
printf("\nClass=ATKT");
}
}
}else
printf("\nEnter valid marks");


 getch();
}
/*=============================================================================================================
OUTPUT
Enter marks m1:44
Enter marks m2:55
Enter marks m3:66
Enter marks m4:55
Enter marks m5:66
Sum of marks is:286
Percentage of marks is:57.00
class=second
==============================================================================================================*/